Weigh Gravity With Slow Motion
β¨ A phone's slow-motion mode becomes a laboratory timer accurate to a few thousandths of a second.
π§° You need
- a phone that records slow motion
- a measuring tape taped vertically to a wall
- a small dense ball
- books to prop the phone steady
- paper and a calculator
β οΈ Drop the ball away from people, windows and the phone itself.
π What you will see
Distance fallen grows faster and faster, so distance against time is a curve. Distance against time squared is a straight line through the origin. Doubling the gradient gives a value for g usually between 9.2 and 9.9, depending on how carefully you read the scale.
π§ͺ Do it
- Tape the measuring tape flat to the wall so the scale is clearly readable on camera.
- Prop the phone on books about two metres away, framing the whole fall, and find out its slow-motion frame rate.
- Hold the ball at the top of the scale, start recording and release it from rest without any push.
- Step through the video frame by frame and note the height for each frame after release.
- Convert frame numbers to times by dividing by the frame rate, and tabulate distance fallen against time.
- Plot distance fallen against time squared and draw the best straight line.
- Take the gradient as half of g, double it, and compare your value with 9.81 metres per second squared.
π‘ Why it happens
An object released from rest and pulled only by gravity accelerates at a constant rate g, so the distance fallen is given by s equals one half g t squared. Plotting s against t squared therefore gives a straight line whose gradient is g divided by two, which is why the graph is drawn that way rather than against t. A video at a known frame rate stamps a precise time on every frame, so the camera becomes a timing instrument far better than a hand-held stopwatch. Air resistance always makes the measured value a little low, and it matters far more for a light object than a dense one.
π Now try this
Repeat with a table-tennis ball and a crumpled paper ball and compare the value of g you calculate for each.
π€ Think about it
Why does your measured value come out slightly below 9.81 rather than above it?
π§ Ask the Acharya
βWhy does your measured value come out slightly below 9.81 rather than above it?β β ask him and he will explain it from your own chapters.
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